Tests for Sulphide Ion

The reaction between sulphide ion and sodium nitroprusside is 

Which of the following product is obtained in the test of sulphide ion with sodium nitroprusside?

Which of the following compound is used to test for the presence of sulphide ion?

What happens when hydrogen sulphide reacts with sodium nitroprusside solution?

A gas obtained by addition of $\mathrm{dil}.{\mathrm{H}}_2{\mathrm{SO}}_4$ to an unknown mixture, which turns lead acetate paper black. The unknown mixture contains:

Given below are two statements:
Statement-I: The gas liberated on warming a salt with dil ${\mathrm{H}}_2{\mathrm{SO}}_4$, turns a piece of paper dipped in lead acetate into black, it is a confirmatory test for sulphide ion.
Statement-II: In statement-I the colour of paper turns black because of formation of lead sulphite.
In the light of the above statements, choose the most appropriate answer from the options given below:

Cotyledons are also called-

Sometimes yellow turbidity appears on passing ${\mathrm{H}}_2\mathrm{S}$ gas, even in the absence of the second group radicals. This happens because

The best explanation for the solubility of $MnS$ in dil. $HCl$ is that

Mixture is heated with dil. $H_{2}S{O}_4$ and the lead acetate paper turns black by the evolved gases. The mixture contains

Sodium nitroprusside when added to an alkaline solution of sulphide ions produce a

Which of the following gives black precipitate when $H_{2}S$ gas is passed through its solution

Sodium nitroprusside, when added to an alkaline solution of sulphide ions, produces purple colour ion due to the formation of

Sodium sulphide on heating with dilute $HCl$ liberates a gas which

$\mathrm{N}{\mathrm{a}}_2\mathrm{S}+\mathrm{N}{\mathrm{a}}_2\left[\mathrm{F}\mathrm{e}{\left(\mathrm{C}\mathrm{N}\right)}_5\mathrm{N}\mathrm{O}\right]$ $\to$ Purple colour. It is due to

$\mathrm{X} \left(\mathrm{Black}\right)\stackrel{{\text{dilute H}}_2{\text{SO}}_4}{\to }\mathrm{Y} \left(\mathrm{g}\right)\stackrel{{\text{dilute HNO}}_3}{\to }$Colloidal sulphur.

Identify $\mathrm{X}$.

Give the correct order of initials T or F for the following statements. Use T if the statement is true and F if it is false.

(I) Sulphide ions reacts with ${\mathrm{Na}}_2\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_5\right(\mathrm{NO}\left)\right]$ to form a purple coloured compound ${\mathrm{Na}}_4\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_5\right(\mathrm{NOS}\left)\right]$. In the reaction, the oxidation state of iron changes

(II) $\mathrm{Pt}\left(\mathrm{IV}\right)$ compounds are relatively more stable than $\mathrm{Ni}\left(\mathrm{IV}\right)$ compounds

(III) The welding of magnesium can be done in the atmosphere of helium

(IV) ${\mathrm{LiAlH}}_4$ on hydrolysis will give ${\mathrm{H}}_2$